Example: Find the price and construction
materials Quantity for a stone masonry wall that
has 50
meters length, 0.6 m width, and 2m height. The mixture ratio is (1: 4).
More Information about site location:
The price of one cubic
meter of Stone is: 11 USD.
The price of one cubic Sand
is: 6.4 USD.
The price of 1 bag Cement
is: 4.5 USD.
The price of one liter of
water is 0.001 USD.
Wage for Unskilled labor, 5
USD
Wage Skilled labor 13 USD
Total Volume of Stone
masonry (V) => V=Length x width x hight = L x W x H = 50 x 0.6 x 2= 60 Cubic meter.
For
one cubic meter, 35% of the concrete mixture considered.
Concrete mixture (V1) => V1= 60 x 35%) = 21 m3
Dry Stone (V2) => V2 = 60-21=39 m3
Concrete mixture ratio is 1:4 (1-part cement + 4-part
sand/gravel) 1+4 = 5 & Total concrete volume = 21 m3, (for
dry Volume = V1 x 1.53) = 21 x 1.53 = 32.13
Total Cement:
32.13/5 x 1 = 6.42 m3 Cement, Density of cement =
1440 kg/ m³
=>> 6.42 x 1440 = 9244.8 Kg. 1 big cement = 50
Kg, 9244.8/50 = 185 Big.
Total Sand/gravel: 32.13/5
x 4 = 26 m3
(Construction Materials: Dry stone 39 m3, Cement
185 Bigs, Sand 26 m3)
Unskilled labor (Worker):
For 1 Cubic meter Stone 1.2 worker considered, Total worker for 60 Cum Stone
Masonry= 60 x 1.2 = 72 unskilled workers.
Skilled labor (Worker): For 1 Cubic meter Stone 0.6 Skilled worker
considered, Total worker for 60 Cum Stone Masonry= 60 x 0.6 = 36 skilled workers.
For one cubic meter stone masonry 72 lit water
considered.
Total water required: 72 x 60 = 4320 lit
|
No |
Description |
Quantity |
Unit |
Unit price |
Total Price |
|
1 |
Total Dry Volume - Stone |
39 |
Cum |
11 US$ |
429 US$ |
|
2 |
Total Cement |
185 |
Big |
6.4 US$ |
1,184 US$ |
|
3 |
Total Sand/Gravel |
26 |
Cum |
4.5 US$ |
117 US$ |
|
4 |
Total Skilled labor |
36 |
Person |
13 US$ |
468 US$ |
|
5 |
Total Unskilled Labor |
72 |
Person |
5 US$ |
360 US$ |
|
6 |
Total required water |
4320 |
liter |
0.012 US$ |
51.84 US$ |
|
Total Price |
2,609.84 US$ |
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